[PD] sending messages instead of signals to dac~

[Peter P.]

Dear IOhannes,

crazy, thank you for the pristine explanation, is makes sense now!
What still puzzles me is that [dac~] does not output a signal when it
receives the "1" message.

Thanks again,
P

* IOhannes m zmölnig <zmoelnig at iem.at> [2021-12-06 19:04]:
> On 12/6/21 17:57, Peter P. wrote:
> > Is this know, explainable and does it "mean" something? ;)
> 
> it's known (that is: the group of problems to which this one belongs)
> 
> here's a layman explanation (that i haven't actually checked with the source
> code):
> 
> whenever you patch with signal objects (that is: create a new object~,
> delete a object~, connet object~s), the DSP graph gets re-compiled (if dsp
> is on).
> this is not true for non-signal objects: adding/connecting non-signal
> objects is not going to change the DSP graph, so it is not re-compiled
> (however, it does need to be recompiled if you remove a non-signal
> object...why? just think [table]).
> 
> now with your single [dac~] object, there is not much of a DSP-graph to
> compute, so Pd obviously does nothing. esp. the float-to-signal conversion
> seems to be not activated yet.
> adding a single msgbox and connecting it to [dac~] doesn't change anything
> in this regard, so Pd doesn't "notice" that it now has to actually do the
> float-to-signal forwarding.
> 
> you can force a re-compilation of the DSP graph (which will make Pd pick up
> the float-to-signal conversion) by saving your patch (notice that get the
> click).
> you can also force it by removing any object (or msgbox!) - which you
> already know.
> 
> you could also connect a [sig~ 0] to the *second* inlet of the [dac~] tat
> the beginning: this will not do much except creating a (small) DSP-graph of
> which [dac~] is part of.
> if you then create you msgbox and send [1( to the *first* (otherwise
> unconnected) inlet of [dac~] you also get a click.
> 
> 
> gfmds
> IOhannes




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