[PD] rsqrt~

[siggmuss]

hi, how can i make a reciprocal square root without using the rsqrt~
object?
i know rsqrt (x) = 1/sqrt(x)
and im trying  [sig~ 1]-> [/~ ]<- [sqrt~ x] but i cant put signals to the
right inlet of
/~ , when i put an unsig~ it doesnt work , i need a signal because i want
to connect the result to rifft~

any idea?

thanks in advance

siggmus

-- 
http://www.fastmail.fm - One of many happy users:
  http://www.fastmail.fm/docs/quotes.html