[PD] backwards ead~

[Stephan Elliot Perez]

Greetings,
     Thank you for your responses.  I tried your suggestion, hardoff, and
the result is the attached [ead-reverse~].  Unfortunately, the expression
behaves differently with this [vline~]-construction as with the [phasor~].
Here, if 1 is entered into the right input of [expr~], the result is an
envelope whose steepness becomes exponentially smaller while ascending and
exponentially greater while descending (if near 0, the opposite form is
produced and values between 1 and 0 produce a divided, confused form). I
however wish to produce an envelope that becomes exponentially steeper both
ascending and descending.
     My problem with this [expr~] as well as with Mr. Farnell's patches is
that I do not quite understand the math behind them.  Any ideas?

Best regards,
Stephan Elliot Perez


On Fri, May 27, 2011 at 5:54 PM, hard off <hard.off at gmail.com> wrote:

> instead of the [phaser~], send a [line~] (or [vline~]) signal.
>
> for example:
>
> [1, 0.5 500, 0 1000 500(
> |
> [vline~]
>
>
> like most of my patches, i don't think i originally made that one, someone
> else posted it, and i just copied.   ;)
> must have been a long time ago though, cos i barely remember it.
>
>
>
>
> On Sat, May 28, 2011 at 12:24 AM, Stephan Elliot Perez <
> dreamoftheshoreofanotherworld at gmail.com> wrote:
>
>> Greetings,
>>        I wish to produce a wave form with the opposite form of the normal
>> ead~ wave (the curves become exponentially steeper instead of flatter),
>> which I can achieve by entering a negative number into the phasor in hard
>> off's exact-ead~ patch, which I downloaded from the archive.  However, I
>> still want to be able to independently change the length of the ascent,
>> decline, and distance between waves as is possible with ead~.  Does anyone
>> know how I could do this, or possibly have access to an abstraction-version
>> of ead~?
>>
>> Best regards,
>> Stephan
>>
>>
>>
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>
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